#include<stdio.h>
#include<conio.h>
void main()
{
float x[100],y[100],value2,value,fx,h;
int i,size;
clrscr();
printf("How many value you want to enter: ");
scanf("%d",&size);
for(i=0; i<size; i++)
{
printf("Enter elements of x[%d]:\n",i);
scanf("%f",&x[i]);
printf("Enter elements of y[%d]:\n",i);
scanf("%f",&y[i]);
}
h = x[2]-x[1];
printf("\nh = %f",h);
for(i=1; i<size-1; i++)
{
if(i%3==0)
value2 += 2*y[i];
else
value += 3*y[i];
}
printf("value2 = %f \n value = %f",value2, value);
fx = ( h*3)/8 * ( y[0] + y[size-1] + value + value2 );
printf("\nf(x)= %f",fx);
getch();
}
there is some good c ,java, sql and vb6 programs,Windows tricks, sms shorthand etc
Friday, March 30, 2012
WAP of Simpson3/8 in C
/* WAP of Simpson3/8 in C */
Thursday, March 29, 2012
WAP of Switch case in Java
/*WAP to capture the two integer values from user and perform following actions according to user Requierement
1. Addition
2. Substraction
3. Multiplication
4. Division
5. Exit
*/
1. Addition
2. Substraction
3. Multiplication
4. Division
5. Exit
*/
import java.lang.*;
import java.io.*;
class oprations
{
public void InputMsg()
{System.out.println("Enter Two Integer numbers. ");}
public void continueMsg()
{System.out.println("Do you want to Continue. \n1. Yes \n0. No");}
public static void main (String args[]) throws IOException
{
int a , b, choice = -1 ;
do
{
System.out.println("Choose a Opration");
System.out.println("1. Addition \n2. Substraction \n3. Multiplication \n4. Division \n5. Exit \nYour Choice: ");
BufferedReader br = new BufferedReader(new
InputStreamReader(System.in));
oprations e = new oprations();
choice = Integer.parseInt(br.readLine());
int repeate = -1;
do
{
switch(choice)
{
case 1: e.InputMsg();
a = Integer.parseInt(br.readLine());
b = Integer.parseInt(br.readLine());
System.out.println("Addition = "+(a+b));
e.continueMsg();
repeate = Integer.parseInt(br.readLine());
break;
case 2: e.InputMsg();
a = Integer.parseInt(br.readLine());
b = Integer.parseInt(br.readLine());
System.out.println("Substraction = "+(a-b));
e.continueMsg();
repeate = Integer.parseInt(br.readLine());
break;
case 3: e.InputMsg();
a = Integer.parseInt(br.readLine());
b = Integer.parseInt(br.readLine());
System.out.println("Multiplication = "+(a*b));
e.continueMsg();
repeate = Integer.parseInt(br.readLine());
break;
case 4: e.InputMsg();
a = Integer.parseInt(br.readLine());
b = Integer.parseInt(br.readLine());
System.out.println("Division = "+(a/b));
e.continueMsg();
repeate = Integer.parseInt(br.readLine());
break;
case 5: System.out.println("BYE!");
break;
default: System.out.println("Invalid Input.");
}
}while(repeate != 0 && choice != 5);
}while(choice != 5);
}
}
WAP of Bubble Short in C++
/*WAP of Bubble Short in C++*/
#include<iostream.h>
#include<conio.h>
class bubbleShort
{
int size, a[100];
public:
void getdata();
void sorting();
};
void bubbleShort :: getdata()
{
int i;
cout << "\nEnter total number of elements: " ;
cin >> size;
cout << "\nEnter elements: ";
for(i=0;i<size;i++)
cin >> a[i];
cout << "\nEntered elements are: ";
for(i=0;i<size;i++)
cout << a[i] << " ";
}
void bubbleShort :: sorting()
{
int i,j,temp;
for(i=1;i<size;i++)
{
for(j=0;j<size-i;j++)
{
if(a[j]>a[j+1])
{
temp=a[j];
a[j]=a[j+1];
a[j+1]=temp;
}
}
}
cout << "\nElements After Shorting:";
for(i=0;i<size;i++)
cout << "\n" << a[i];
}
void main()
{
clrscr();
bubbleShort bsrch;
bsrch.getdata();
bsrch.sorting();
getch();
}
WAP of Linear Search in C++
/*WAP of Linear Search in C++*/
#include<iostream.h>
#include<conio.h>
class linearSearch
{
int size, a[100],item;
public:
void setData();
void searchItem();
};
void linearSearch :: setData()
{
int i;
cout << "\nEnter total number of elements: " ;
cin >> size;
cout << "\nEnter elements: ";
for(i=0;i> a[i];
cout << "\nEnter Item which you want to find: ";
cin >> item;
}
void linearSearch :: searchItem()
{
int k=1, loc=0;
while(loc==0 && k<=size)
{
if(item == a[k-1])
{
loc = k;
}
k +=1;
}
if(loc==0)
cout << "\n" << item << " isn't Found.";
else
cout << "\n" << item << " at Location " << loc;
}
void main()
{
clrscr();
linearSearch bsrch;
bsrch.setData();
bsrch.searchItem();
getch();
}
WAP of Matrix Multiplication in Java
/*WAP of Matrix Multiplication in Java*/
import java.lang.*;
import java.io.*;
import java.util.*;
class matrix
{
public static void main (String args[]) throws IOException
{
int a[][] = new int[2][2];
int b[][] = new int[2][2];
int c[][] = new int[2][2];
Scanner sc = new Scanner(System.in);
System.out.println("Enter Elements of Matrix 1");
for(int i=0; i<2; i++)
{
for(int j=0; j<2; j++)
{
a[i][j] = sc.nextInt();
}
}
System.out.println("Enter Elements of Matrix 2");
for(int i=0; i<2; i++)
{
for(int j=0; j<2; j++)
{
b[i][j] = sc.nextInt();
}
}
// calculation
for(int i=0; i<2; i++)
{
for(int j=0; j<2; j++)
{
for(int k=0; k<2; k++)
{
c[i][j] += a[i][k] * b[k][j];
}
}
}
System.out.println("Matrix After multiplication");
for(int i=0; i<2; i++)
{
for(int j=0; j<2; j++)
{
System.out.println( "\t" + c[i][j] );
}
}
}
}
Tuesday, March 20, 2012
WAP of Simpson's 1/3
/* WAP of Simpson's 1/3 */
#include<stdio.h>
#include<conio.h>
void main()
{
float x[100],y[100],odd, even,fx,h;
int size,i;
clrscr();
printf("How many value you want to enter: ");
scanf("%d",&size);
for(i=0; i<size; i++)
{
printf("Enter elements of x[%d]:\n",i);
scanf("%f",&x[i]);
printf("Enter elements of y[%d]:\n",i);
scanf("%f",&y[i]);
}
h = x[2]-x[1];
printf("\nh = %f",h);
for(i=1; i<size-1; i++)
{
if(i%2==0)
{
even += 2*y[i];
}
else //if(i%2 != 0)
{
odd += 4*y[i];
}
}
fx = ( h/3) * ( y[0] + y[size-1] + odd + even );
printf("\nf(x)= %f",fx);
getch();
}
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